Print Address of variable Using Pointers

 Question :

Write a program to print the address of a variable. Use this address to get the value of this variable.

#include<stdio.h>

 

int main()

{

    int a = 111;

    int *ptr;

    ptr = &a ;

   

    printf("The address of variable a is : %u\n", &a);

    printf("The value of variable a is : %d\n", *(&a));

    printf("The value of variable a is : %d\n", *ptr);

 

return 0;

}

OUTPUT--->

The address of variable a is : 6422216 The value of variable a is : 111 The value of variable a is : 111

  

Call By Reference

 #include<stdio.h>

int swap(int *a, int *b);

int main()

{

    int x = 4, y = 8;

    printf("The value of x and y before swap is : %d and %d\n", x,y);

    swap(&x,&y);

    printf("The value of x and y before swap is : %d and %d\n", x,y);

return 0;

}

int swap(int *a, int *b){

    int temp;

    temp = *a;

    *a = *b;

    *b = temp;

}

OUT PUT--->

The value of x and y before swap is : 4 and 8 The value of x and y before swap is : 8 and 4

Call By Value

 #include<stdio.h>

int sum(int a, int b);

 

int main()

{

    int a=99,b=12;

    printf("The value of 99 + 12 is: %d", sum(a,b));

 

return 0;

}

int sum(int a, int b){

    return a+b;

}

ANS--->

The value of 99 + 12 is: 111

Print Pattern

 

#include<stdio.h>

int main(){

    int n=5;

    for(int i=1 ; i<=n; i++){

        for(int j=1; j<=(2*i-1); j++){

            printf("*");

        }

        printf("\n");

    }

return 0;

}

ANS--->

*

*** ***** ******* *********

Pyramid - Pattern

 #include<stdio.h>

int main(){

   

    int n=3;

    for(int i=1 ; i<=n; i++){

        for(int j=1; j<=(n-i); j++){

            printf(" ");

        }

        for(int k=1; k<=(2*i-1); k++){

            printf("*");

        }

        printf("\n");

    }

return 0;

}

ANS----->

*

*** *****

To Find Simple Interest

 # include<stdio.h>

int main()

{

   int principal = 100, rate= 6, year= 1;

   int simpleInterest= (principal*rate*year)/100;

   printf("The value of simple iterest is: %d\n", simpleInterest);

    return 0;

}

Addition Program

 # include<stdio.h>

int main()

{

   

    int a = 4;

    int b = 16;

    printf ("The Addition Of a and b is %d \n", a+b);

    return 0;

}